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(2x-1)\Xb2=(X+1)\Xb2 Quadratic Equation In Standard Form
(2x-1)²=(x+1)² quadratic equation in standard form Answer: 3x² - 6x = 0 Step-by-step explanation: In quadratic equation, the standard form is ax² + bx + c = 0 In the given equation (2x-1)²=(x+1)² We have to simplify it first (2x-1)²=(x+1)² (2x - 1)(2x - 1) = (x + 1)(x + 1) 4x² - 4x + 1 = x² + 2x + 1 4x² - x² - 4x - 2x + 1 - 1 = 0 3x² - 6x = 0
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