(2x-1)\Xb2=(X+1)\Xb2 Quadratic Equation In Standard Form

(2x-1)²=(x+1)² quadratic equation in standard form

 

Answer:

3x² - 6x = 0

Step-by-step explanation:

In quadratic equation, the standard form is

ax² + bx + c = 0

In the given equation

(2x-1)²=(x+1)²

We have to simplify it first

(2x-1)²=(x+1)²

(2x - 1)(2x - 1) = (x + 1)(x + 1)

4x² - 4x + 1 = x² + 2x + 1

4x² - x² - 4x - 2x + 1 - 1 = 0

3x² - 6x = 0


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